Chemical Kinetics ke NEET previous year questions, saal ke hisaab se. Option dabao, instantly check karo, aur step-by-step solution dekho. Har answer NTA ki official answer key se match kiya hua.
2 questions1 paper
Q1NEET 2025Q.56Easy
If the half-life ($t_{1/2}$) for a first order reaction is 1 minute, then the time required for 99.9% completion of the reaction is closest to:यदि किसी प्रथम कोटि की अभिक्रिया की अर्धायु ($t_{1/2}$) 1 मिनट है, तो अभिक्रिया के 99.9% पूर्ण होने में लगने वाला समय लगभग है:
Sahi answer: (4)
First order: $t = \frac{2.303}{k}\log\frac{[A]_0}{[A]}$ and $k = \frac{0.693}{t_{1/2}}$. For 99.9% completion, $\frac{[A]_0}{[A]} = 1000$, so $\log 1000 = 3$. $t = \frac{2.303 \times 3}{0.693} \times t_{1/2} \approx 10\,t_{1/2} = 10$ minutesप्रथम कोटि: $t = \frac{2.303}{k}\log\frac{[A]_0}{[A]}$ और $k = \frac{0.693}{t_{1/2}}$। 99.9% पूर्णता के लिए $\frac{[A]_0}{[A]} = 1000$, इसलिए $\log 1000 = 3$। $t = \frac{2.303 \times 3}{0.693} \times t_{1/2} \approx 10\,t_{1/2} = 10$ मिनट
Q2NEET 2025Q.89Easy
If the rate constant of a reaction is 0.03 $\text{s}^{-1}$, how much time does it take for 7.2 mol $\text{L}^{-1}$ concentration of the reactant to get reduced to 0.9 mol $\text{L}^{-1}$? (Given: log 2 = 0.301)यदि किसी अभिक्रिया का वेग स्थिरांक 0.03 $\text{s}^{-1}$ है, तो अभिकारक की सांद्रता 7.2 mol $\text{L}^{-1}$ से घटकर 0.9 mol $\text{L}^{-1}$ होने में कितना समय लगेगा? (दिया है: log 2 = 0.301)
Sahi answer: (1)
The unit $\text{s}^{-1}$ shows it is a first order reaction. $t = \frac{2.303}{k}\log\frac{[A]_0}{[A]} = \frac{2.303}{0.03}\log\frac{7.2}{0.9} = \frac{2.303}{0.03}\log 8$ $\log 8 = 3 \times 0.301 = 0.903$ $t = 76.77 \times 0.903 \approx 69.3$ sइकाई $\text{s}^{-1}$ बताती है कि यह प्रथम कोटि की अभिक्रिया है। $t = \frac{2.303}{k}\log\frac{[A]_0}{[A]} = \frac{2.303}{0.03}\log\frac{7.2}{0.9} = \frac{2.303}{0.03}\log 8$ $\log 8 = 3 \times 0.301 = 0.903$ $t = 76.77 \times 0.903 \approx 69.3$ s
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